(2^2x+3)+4=33(2^x)

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Solution for (2^2x+3)+4=33(2^x) equation: 



(2^2x+3)+4=33(2^x)

We move all terms to the left:

(2^2x+3)+4-(33(2^x))=0

determiningTheFunctionDomain
(2^2x+3)-332^x+4=0

We get rid of parentheses

2^2x-332^x+3+4=0

We add all the numbers together, and all the variables

2^2x-332^x+7=0

We move all terms containing x to the left, all other terms to the right

2^2x-332^x=-7

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